For AES-128, the block cipher works on 128 bits at a time. Whichever block cipher mode you use (ECB, CBC, CTR, etc.), the encrypting will always be done on 128-bit blocks. The assumption is also made that padding is being used.
Let's assume that $m = (a||b||c)$ and that $m' = (c||a||b)$. That gives us two separate messages, each 900 bits.
Using $V_1=E_k(m)$ and $V_2=E_k(m')$, you can say that $V_1 \neq V_2$.
Depending on the block cipher mode you're using (ex: Electronic Codebook), however, it is quite possible that individual 128-bit cipher blocks may be identical between $m$ and $m'$. For CBC, you should not have identical cipher blocks in this scenario.
*N.B. I've found Practical Cryptography by Niels Ferguson and Bruce Schneier to be a good source of information for researching and answering these sorts of questions.