Take the 2-minute tour ×
Cryptography Stack Exchange is a question and answer site for software developers, mathematicians and others interested in cryptography. It's 100% free, no registration required.

I am currently trying to create an ECCCurve for E-521. Unfortunately, it is not currently a named curve in the library I am using, so I will have to define it manually.

I am using the definition of the E-521 curve provided here:

E521 is a curve over GF(2^521-1), formula x^2+y^2=1-376014x^2y^2,
5003276673749012051148356041324, 12), order 2^519 -
85779108655765, cofactor 4.

The two curve definitions I can choose from are FpCurve and F2mCurve. I'm not sure which one to choose for this. I have looked here. Unfortunately, I don't know how to extrapolate which one to use based just on the knowledge that E-521 is an Edwards curve.

Is an Edwards curve not compatible with the base classes that are defined in the library? Do I need to wait for further development there, or can I risk attempting to implement it myself? The latter is obviously a question I will likely have to answer myself, but some extra information on the risks/other implementations I could examine would be helpful.

share|improve this question
FpCurve is for prime fields, F2mCurve for binary fields. This field is prime, so you need to choose FpCurve. –  CodesInChaos Mar 12 '14 at 19:35
I suspect this library only supports weierstrass form, so you'd need to either convert (bad idea IMO) or implement a custom EccPoint class with edwards arithmetic. But last time I checked BC C# had quite bas ECC implementations. Not resistant to side channel attacks and slow as hell (using affine coordinates). –  CodesInChaos Mar 12 '14 at 19:38
I would use a Montgomery curve myself. –  Richie Frame Mar 12 '14 at 19:39
That makes sense. Unfortunately, it's what we're relegated to without implementing our own ECC. The FpCurve takes in three BigIntegers, q, a, and b. The question is really, how do I map the definition of the curve to these parameters? I'll look in to the Montgomery though, as it seems (according to SafeCurves) to fit our needs as well. –  Nate Diamond Mar 12 '14 at 22:13
Ah, I think I have found it. If I'm reading this correctly and assuming that BC implemented the basic Weierstrass-form, then I have to implement the Montgomery form myself or convert it to Weierstrass form. Am I reading this correctly? Are there any performance considerations in this? –  Nate Diamond Mar 12 '14 at 23:32

2 Answers 2

Bouncy Castle does not support curves of the Edwards form (such as the one E-521 has). See related question: Elliptic Curves of different forms

Bouncy Castle's FpCurve supports curves of the Weierstrass simple form. You can convert Edwards curves to this form by a series of (complex) calculations. SafeCurves shows you the necessary equations. First convert the Edwards curve to Montgomery form, then to Weierstrass form.

Unfortunately doing this will result in absolutely huge numbers, which - on top of the fact that Edwards curves are computed faster than Weierstrass curves - results in poor performance.

Appendix: Curve forms

  • Weierstrass: $y^2 = x^3 + ax + b$
  • Montgomery: $By^2 = x^3 + Ax^2 + x$
  • Edwards: $x^2 + y^2 = 1 + dx^2y^2$
share|improve this answer

Edwards Curves can be converted to Montgomery or Weierstrass curves.

The only tricky part is that the point (0, 1) goes to the point at infinity. Here is some haskell that will do it. (Requires arithmoi package for extended gcd)

{-# LANGUAGE NoImplicitPrelude #-}
module E521 (p521, IntModp521, toIntModp521, fromIntModp521,
             d, a_montgomery, b_montgomery, a_weierstrass, b_weierstrass,
             bp, bp_montgomery, bp_weierstrass)

import Data.Ratio (numerator, denominator)
import Math.NumberTheory.GCD (extendedGCD)
import Prelude ( Eq(..), Fractional(..), Num(..), Ord(..), Show(..),
                 (^), ($), mod, otherwise)

p521 :: Integer
p521 = 2^521 - 1

newtype IntModp521 = IntModp521 Integer deriving (Show, Eq)
toIntModp521 :: Integer -> IntModp521
toIntModp521 x | x < 0     = IntModp521 $ (x `mod` p521) + p521
                   | otherwise = IntModp521 $ (x `mod` p521)
fromIntModp521 (IntModp521 x) = x

instance Num IntModp521 where
  (IntModp521 x) + (IntModp521 y) = IntModp521 $ (x + y) `mod` p521
      (IntModp521 x) * (IntModp521 y) = IntModp521 $ (x * y) `mod` p521
  abs (IntModp521 x) = IntModp521 $ x
  negate (IntModp521 x) = toIntModp521 (-x)
  fromInteger = toIntModp521
  signum (IntModp521 0) = 0
  signum _              = 1

instance Fractional IntModp521 where
  recip (IntModp521 x) = IntModp521 $ middle $ extendedGCD x p521
      middle (a, b, c) = b
  fromRational a = (toIntModp521 (numerator a)) / (toIntModp521 (denominator a))

d :: IntModp521
d = -376014

bp :: (IntModp521, IntModp521)
bp = (x, y)
    x = 1571054894184995387535939749894317568645297350402905821437625181152304994381188529632591196067604100772673927915114267193389905003276673749012051148356041324
    y = 12

a_montgomery :: IntModp521
a_montgomery = 2 * (1 + d) / (1 - d)

b_montgomery :: IntModp521
b_montgomery = 4 / (1 - d)

a_weierstrass :: IntModp521
a_weierstrass = (3 - a_montgomery ^ 2) / (3 * b_montgomery ^ 2)

b_weierstrass :: IntModp521
b_weierstrass = (2 * a_montgomery ^ 3 - 9 * a_montgomery) / (27 * b_montgomery ^ 3)

bp_montgomery = (u, v)
    u = (1 + y) / (1 - y)
    v = u / x
    (x, y) = bp

bp_weierstrass = (u, v)
    u = (x + a_montgomery / 3) / b_montgomery
    v = y / b_montgomery
    (x, y) = bp_montgomery
share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.