Suppose that you see all IP communication packets between two computers for a day, as they pass through a connecting router, and this amounts to 10MB. You additionally know that all data transmission follows the standard "RSA-1024 plus AES-128" protocol. To be even more specific, suppose you know only one computer is doing RSA decryption, which computer that is, its specific "public key", and that the RSA decryption is only done to re-initiate the AES key after the other computer is (instantly) rebooted.
COULD YOU LOOK AT THE 10MB AND GET ANY INFORMATION ABOUT WHETHER THE COMPUTER WAS REBOOTED?
I wonder if these pseudo-random streams could be "hashed" in some way to help...e.g., maybe 0.03 bits of information is revealed ("Because of this abnormal XXX data series in the stream, there is a 60% chance it was rebooted, instead of the normal 50%.").
I know that any revealing (even a tiny part of a single bit as useless as the rebooting of a computer) is against the goal of this encryption, so I ask in a rigorous way for those familiar with these protocols and their outputs. I truly wonder if there isn't some blatant unencrypted "I need to login from scratch, please!" signal in the standard protocols. When a computer loses its AES key, they could be blatant to help the server, or they could rely on the server to use AES first, conclude it's gibberish, and then try RSA. I'm guessing the latter is done, but hoping for confirmation here.
To answer my own question, I do believe that 0.03 bits would be reasonable, mainly due to the timing of the packets. RSA encryption/decryption takes longer, so delayed responses correlate with a reboot (please notice I'm ignoring the actual power-down time and wrote "instantly rebooted" in the problem statement to focus just on the cryptography).
NOTE: We need more information on the protocol to confidently answer this, but I know nothing beyond the AES and RSA algorithms. This is why I ask the question. So, if you must, please just assume the server URL is "https://facebook.com" or choose a common reasonable protocol. Thanks!