Factorization is the problem of taking an integer and finding the set of prime numbers that produce the integer when multiplied together. For large integers with large factors, factorization is hard and is the basis for cryptosystems like RSA.
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How big an RSA key is considered secure today?
I think 1024 bit RSA keys were considered secure ~5 years ago, but I assume that's not true anymore. Can 2048 or 4096 keys still be relied upon, or have we gained too much computing power in the ...
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3answers
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Modern integer factorization software
What are the modern software packages that can be used to factoring large numbers into primes. By modern I mean developed and made public within the last 5 years. I'm interested in things that are ...
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5answers
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Is it feasible to build an index of prime factors?
Would it be possible to break an RSA key, in for example 1 week of time, if the cracker have already spent X number of years building an index of primes by performing every permutation of existing ...
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2answers
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RSA and prime difference
It is known that the two prime factors $p$ and $q$ of an RSA modulus $n$ should not be too close to each other, otherwise an attacker may factor the modulus. In other words, $\Delta = \left| p - q ...
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RSA security assumptions - does breaking the DLP also break RSA? [duplicate]
Possible Duplicate:
Would the ability to efficiently find Discrete Logs have any impact on the security of RSA?
I'm wondering if breaking the DLP, that is the basis for ElGamal and DSA, ...
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1answer
219 views
Why are elliptic curve variants of RSA “chiefly of academic interest”?
Yesterday I was thinking about elliptic curve variants of popular protocols/algorithms (ECDH, ECES[1], etc) and the thought occured that I had never seen an elliptic curve variant of RSA. My ...
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Security relevance of random factor in Paillier
In the Paillier cryptosystem [1] the encryption of $m \in \mathbb{Z}_N$ with randomness $r \in \mathbb{Z}_n^*$ is $c = g^m r^n \bmod{n^2}$.
The additive-homomorphic property of the system shows that
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