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How difficult is it to find the “pre-image” of a block cipher?

Say that I have $$ C_1 = AES_{k_1}(M_1) $$ How difficult would it be to find a key, K2 and plaintext M2 $$ C_2 = AES_{k_2}(M_2) $$ such that $$ C_1 == C_2 $$ How would using a block cipher ...