Hot answers tagged algorithm-design
Actually you have a bug in your step of key generation, it should be $Q_A=d_A \times G$ and you want to have a point $G$ of large prime order $n$ such that the ECDLP is hard on the group. The last check ensures that the public key $Q_A$ is a point of order $n$. If this is the case, then $Q_A\times n = (d_A \times G)\times n = d_A\times(n\times G)=d_A\times ...
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