# Tag Info

No. Yes, by choosing an authenticated encryption scheme with a known $\:I\hspace{.03 in}V\hspace{.04 in}||\hspace{.04 in}C\hspace{.04 in}||\hspace{.04 in}tag\:$ and $k_{\hspace{.02 in}0}$ and $k_1$ such that decrypting $\:I\hspace{.03 in}V\hspace{.04 in}||\hspace{.04 in}C\hspace{.04 in}||\hspace{.04 in}tag\:$ with $k_{\hspace{.02 in}0}$ and $k_1$ yields ...