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3

I would think these numbers would have been put on the google search engine, and yield (probably) many hits. This assumption is wrong. Certificate serial numbers are not indexed by common search engines, nor are they typically posted to any HTML site. Frankly, I'm not sure why you would assume they'd be indexed. The Wordpress certificate is used for ...


0

This [Carter-Wegman] MAC is not, in general, secure in the quantum setting This is true; however we need to ask "what is this setting, and is it a realistic one?" This setting is one where the adversary can ask queries that are composed of a superposition of quantum states, and the oracle returns the superposition of the answers. In other words, the ...


-2

Actually, a post-quantum security is truly achieveable in a cipher-combo only. So - take a look at AES-finalist-candidates, like Serpent, and use it too or just it, but in 512 bit keys. Here is the starting point for you : enter link description here


1

First, some notes on your choices of primitives: AES-256: You don't need to use AES-256 unless the data you want to protect needs to remain confidential for more than 30 years SHA-256 for authentication. Don't use plain SHA-256. Either use HMAC-SHA-256 using an encrypt-then-authenticate approach or (even better!) use AES-GCM or AES-EAX as your mode of ...


2

FFX is not malleable. It's a strong tweakable pseudo-random permutation, where the "strong" here indicates that both encryption and decryption look like random permutations from the attacker's perspective. In particular, there's no relationship between the plaintexts of closely related ciphertexts (aside from the trivial observation that different ...


3

The authentication tag is defined as an output parameter in GCM (see section 7, step 7 of NIST SP 800-38D). In all the API's I've encountered it's appended to the ciphertext. Where it is actually placed is up to the protocol designer. The protocol designer may well consider the place behind the ciphertext as ad hoc default though. The name "tag" of course ...


-1

It seems that you do want to be given the answer and not just hints, so I will do that. But I'll go step by step so that you can stop reading if you want to finish by yourself. It seems to me that both solutions satisfy the first requirement consisting in authenticity. Breaking this property would consist in changing the content of $R$ to fool $A$ (this ...



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