New answers tagged cbc-mac
3
why overcomplicate it like that,
D1 and D2 generates random 64-bit P
they send it to each other
both generate AES(key,P_own||P_other) and again send to each other (note that these are different for each)
then both can verify that what they received is equal to AES(key,P_other||P_own)
upside here is that it is a symmetric protocol
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