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Is the above example correct? If not, how can the IV to be used for decryption be determined? Yes, it is correct. The vector/mask in CBC mode is generally the previous ciphertext block. The algorithms in 2a and 2b simply extends this notion to the IV so that the CBC mode encryption doesn't have to be re-initialized. The outcome of the IV ...


I suppose you have removed the base64 decoding, so you are working on the raw data. Then indeed the first block is decrypted as if we were in ECB-mode, because after decrypting the first block, we xor with the IV, which is all 0 and indeed has no effect. However, the IV for the next block will be the original previous ciphertext block. So after decrypting ...

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