New answers tagged ciphertext-only-attack
When you have a RSA key pair, it means that you know the private key (otherwise this is not "your" key pair). The private key format, normally, contains the two factors $p$ and $q$ (at least so it goes with PKCS#1). Even if all you have are the modulus $n$, the public exponent $e$ and the private exponent $d$, the factorization of $n$ can still be worked out ...
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