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Decrypt the ciphertext with every possible key and store the result: $2^{56}$ decryptions. Now encrypt the (known) plaintext of the ciphertext with every possible key: $2^{56}$ encryptions. Now you have to check every entry, which is in both lists and try it with another plaintext-ciphertext pair. If you can successfully decrypt that, you are very likely to ...


0

RSA will never become "impractical" until it gets broken. (in polynomial-time) As the best current algorithm to break RSA is subexponential (general number field sieve / GNFS) but according to moore's law, computing power grows exponentially simply increasing key size will always be an option. But beyond 256-bit security ec crypto just is significantly ...


1

Your observations are basically correct. Informally it is as follows: For a uniform PPT algorithm think of a fixed Turing machine that has access to some random tape and the output of the algorithm is a random variable. For non-uniform algorithms it is best to think of a family of circuits indexed by the length of the input (so for every input length the ...



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