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1

Yes this would work as stated by you. Explanation: If you're using a library supporting ECB (which you are actually using in this example) you can input the whole 32 bytes of plaintext and will receive the corresponding 32 bytes of ciphertext. Splitting the operation into two calls doesn't make any difference for libraries as internally they do nothing ...


0

"We are using ECB with RSA": It's difficult to understand what you mean by this; nobody does it, ever, so we have no "default meaning" to fall back on. You will have to describe your protocol in more detail, and then we can tell you why it is flawed.


5

It is highly misleading to call how RSA Encryption is used as 'ECB mode'. With ECB mode, we break the plaintext into N bit segments, and send each one through the block cipher separately. The block cipher is deterministic, and so if two plaintext blocks happen to be the same, so will the corresponding ciphertext blocks. Now, with RSA encryption, we take ...



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