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It's not harder. Solve the DL problem to get $x$ in $Q=x.P$. $Q = \sum_{i=1}^{n} x_i.P = (\sum_{i=1}^{n} x_i).P= x.P$ => any set of $x_i$ that sums to $x$ (modulo the group order) is a solution to ECFP.



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