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You're right in that there's little chance you can break the logarithm in a well-chosen 512 bit group (using a home computer, in reasonable time — as pointed out by SEJPM, it is possible investing some time and a good amount of money). However, in your case, the parameters are bad: The order of $(\mathbb Z/p\mathbb Z)^\ast$, that is $p-1$, is a smooth ...


1

I'll first assume $\phi$ is known, which would be the situation in RSA at key selection. A common method could be to select (odd) $\mu$ at random in some appropriate interval until $\gcd(\mu,\phi)=1$ is satisfied. In the context of RSA, it is fine (if we ignore performance an interoperability issues) to choose an RSA exponent at random in $[3\dots\phi-3]$ ...



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