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how will having a few samples of plaintext-ciphertext pairs help Eve find out p [in the second scheme]? Well, suppose we have four plaintext/ciphertext pairs, and lets look at what is available to the attacker. We make the plaintexts $m_1$, $m_2$, $m_3$, $m_4$, and the corresponding ciphertexts: $$e_1 = a m_1 + b + k_1 p$$ $$e_2 = a m_2 + b + k_2 p$$ ...



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