# Tag Info

No. There are $2^{32}$ ciphertexts that fit into 32 bits. They will decrypt to $2^{32}$ random plaintexts uniformly distributed in the range $\{0, 1, \ldots, 2^{|n|}\}$. Since $|n| \gg 32$ for practical Paillier moduli, the probability of any 32-bit ciphertext encoding a plaintext in $\{0, \ldots, 44\}$ is negligibly small.