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Post-quantum security: As you note, quantum attacks are not known to break lattice-based cryptosystems. But some other proposals like McEliece, as well as most symmetric primitives are not known to be poly-time breakable on a quantum computer. Security from worst case assumptions: In security proofs for cryptosystems we typically assume that some problem ...

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"Cycles" are CPU instruction cycles. Cycles per byte roughly measures how many instructions, in a given instruction set, are needed to produce each byte of output. They're a reasonably-good relative measure of the performance of different algorithms. Generally, when you measure an algorithm's cycles per byte, you use carefully controlled conditions. You ...

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Computations on elliptic curves are more efficient. Roughly speaking, when the base field has size $n$ (for DH/ElGamal/DSA, the size in bits of the modulus $p$; for elliptic curves, the size of the field for point coordinates) and a "security level" $t$ (e.g. $t = 80$ for "80-bit security" as can be expected when using a 160-bit subgroup and a 160-bit hash ...

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From the diagram on CTR mode you can notice that there are no dependencies between any of the phases of the pipeline. If you have more than one block-size worth of data, you can process each block-size chunk completely independently of the others by calculating $\mathrm{ciphertext}_i = E(\mathrm{key}, \mathrm{nonce} \, || \, \mathrm{counter}_i) \oplus ... 5 ECDSA should in general create signatures faster than RSA for the same cryptographic strength if you just look at the mathematics. In the end the modular exponentiation is performed for smaller numbers. However, ECDSA depends on a random number generator, so ECDSA speeds may be slower if the random number generator blocks for any reason (and not using a good ... 5 Pretty much all modern encryption systems (including AES, in any standard mode) are data-agnostic: they are designed to encrypt any byte (or bit) stream regardless of its content, and their performance does not depend in any way on what the stream contains. Indeed, if this were not the case, that would open the encryption scheme to timing attacks — if ... 4 In RSA encryption as practiced (that is, to encipher a message which is a short symmetric key), the message size after padding is fixed and equal to the modulus size. Thus the size of the message has no impact on performance. Calculating a modular inverse is performed only during key generation, that is seldom. Also, it has low cost compared to generating ... 4 Predicting speed by looking at the assembly is hard, especially since processors do all sorts of tricks which have memory (e.g. branch prediction). So yes, this is all about measuring. There is an art to it; for instance, you would rather repeatedly encrypt the same relatively small buffer (4 or 8 kB) so as to avoid cache effects. One method is to do the ... 4 They measure it. Once upon a time, CPUs were simple enough that you really code compute the amount of time for a stretch of code by looking up the clocks per instruction in the manual, add them all together, and that'd be the total time. However, CPU manufacturers have added more and more optimizations and parallelism; this makes the CPUs run faster (for ... 3 Generally, it depends on the architecture. If you have$n$processors available, the obvious way to parallelize CTR mode encryption is to distribute each chunk of$n$consecutive blocks among the processors, so that processor$0 \le i < n$computes: $$C_j = E_K(c_j) \oplus P_j, \quad j = i + kn, k = 0,1,2,\dotsc$$ where$c_j$is the$j$-th counter ... 3 In principle, it is theoretically possible to calculate the time it takes a machine to run some known algorithm. It used to be fairly commonplace, but there are apparently very few people who have ever done it -- the sorts of things that used to require isochronous code are now-a-days generally done in other ways. In practice, it's generally simpler and ... 3 The performance bottleneck with RSA is the modular exponentiation operation. On the other hand, if you are interested in public key encryption performance, perhaps RSA is not the correct tool. RSA is actually fairly fast during its encryption operation; however it is quite slow during the decryption. If you care about decryption performance, you may want ... 3 Elliptic Curve Cryptography (ECC) is not known to be specifically more resistant to side channel attacks (of course the next question is more resistant than what). This paper reviews power analysis side-channel attacks against ECC and countermeasures. Given that ECC uses multiplication and many common implementations of the MUL instruction run in time ... 2$\displaystyle \text{cycles per byte} = \frac{\text{cycles per second}}{\text{bytes per second}} = \frac{2.1 ~ \text{GHz}}{4.3 ~ \text{MiB}} = \frac{2.1 \times 10^9}{4.3 \times 1024^2} \approx 466 ~ \text{cpb}\$ Of course this may be way off because processors are complex beasts these days, and may not work at their full potential all the time, and the ...

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PLEASE NOTE: The code I link to below has not yet been reviewed by anyone with professional cryptography experience. I expect that it contains bugs, and it is definitely not production-ready. I am still learning about the JCA; there are parts of the code I have not finished, and there are parts that I will most likely go back and redo. That said, the tests ...

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Almost every Java .valueOf(byte[] s, int offset, int length) has the same meaning: s is the array to read from. offset is the location in the array to start reading from (inclusive). length is the number of bytes to try and read - "try" because the array may not be long enough to have that many bytes from offset. Remembering that Java arrays are ...

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The performance of the hash depends on the environment it is used in. Keccak excels in ASIC type hardware designs, whereas Blake and Skein excel in x86 and x86-64 environments. MD5 is still quite fast in software, but newer algorithms take advantage of SIMD instructions on newer processors. There is also the question of performance on a per invocation ...

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