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As far as we know, SHA512 acts like a random function. So, the only way we know to find a preimage whose hash starts with 0x12345678, is to go through distinct preimages, and hash each one until we find one that starts with 0x12345678. If the output of SHA512 is equidistributed (and we have no reason to believe it isn't), then the probability of any hash ...

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