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There is no such thing as an incorrect secret. There is just some secret, that must be uniquely defined by the distribution phase.


0

A Flaw If you try working through your example concretely then you should see at least one issue with decoding. Consider values mod $8$: $ A = { 3 } \\ B = {7} \\ secret = {5 } $ Using your equations we have: $ Q = 3 + 7 + 5 = 7 \\ U = 3 - 7 + 5 = 1 $ And for decoding: $ B = (U - Q) / 2 \\ B = (1 - 7) / 2 \\ B = -6 / 2 ({\text mod} 8) $ But what ...


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If you perform the distribution digitally (using networks) then you have a problem. Unless you use another one time pad you lose the perfect confidentiality as the distribution itself won't deliver perfect security. But using another one time pad is pointless: you would lose exactly as many key bits as you are distributing, while you are only protecting the ...



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