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Can someone explain me how the t actually affects the outcome of the procedure (which, as far as I understand, just calculates the eight 64-bit words xor with "a5a5a5a5a5a5a5a5")? That's not right. Both hex 5 and A are encoded setting two bits out of 4; a5 translates to 1010 0101 in bits. I.e. half the bits are flipped. This kind of XOR value is often ...

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