New answers tagged shamir-secret-sharing
This is the correct behavior. Since the degree of the multiplication sharing is $2t$, it will take $2t+1$ shares of either it directly or the subshares. If done on the subshares, the resulting sharing is of degree $t$. Shamir secret sharing is commutative with respect to polynomial evaluation. Let $\sigma_1^t$ be the polynomial for sharing $s$ with degree ...
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