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10

If k is a constant, such as 3, it becomes possible to select a pair (N,g) such that the discrete log of k to the base g is known, which would enable the two-for-one guessing attack again.


8

Oh, and while you did not specifically ask about this, there is another point I believe that is important to highlight; DH and SRP are different protocols, and have different requirements on the generator they use. In particular, taking a generator that is designed to be used securely within DH can void the security properties of SRP. Here's what's going ...


8

Well, yes, that is generally good advice about DH. Here is some background on this: support you were given a value $g^x \bmod p$, and you were also told that $1 \le x \le A$ for some value $A$. If so, then there are several known attacks (such as Big Step/Little Step and Pollard's Rho) that can recover $x$ in about $\sqrt A$ steps. If we have as our ...


6

The security goal behind SRP is that an attacker that could either pretend to be a client (and attempt to log into a server that knows the key), pretend to be a server (and allow clients that know the key to attempt to log in), or actively monitor (and modify) the communications between a valid client and a valid server, would learn nothing from an exchange, ...


4

Yes, you can and use a slow hashing function when constructing the verifier. I would recommend using PBKDF2, as it is designed for this purpose. In fact, Wikipedia says: $v$ is the host's password verifier, $v = g^x$, $x = H(s,p)$. Using of functions like PBKDF2 instead of $H$ for password hashing is highly recommended. Thus, you could use ...


4

From the RFC: SRP also supplies a shared secret at the end of the authentication sequence that can be used to generate encryption keys. It seems from my quick look over the RFC that that shared secret is the premaster secret, so you are correct.


2

The point of SRP is to remove the need for the SSL/TLS certificates. With SRP integrated into SSL/TLS (as per RFC 5054), you get mutual client/server password-based authentication and can do without any of the dreadful certificate business; and yet the protocol is still resilient to offline dictionary attacks. If your SSL/TLS still uses a server certificate ...


2

It seems like a better solution would be to have the server that is providing the Javascript file, also provide a random seed. The Javascript can then use that random seed (and anything other maybe-random bits it can scrounge up, such as the output from Math.random()) to see a cryptographic PRNG, and then use the output of that crypto-PRNG for generating s, ...


1

The multiplier parameter $k$ is different between SRP 6 and 6a. You can see that RFC 5054 calculates it using a hash of the domain parameters (modulus $N$ and generator $g$), so it is using SRP 6a, as opposed to SRP 6 where $k$ is constant. Likewise, in section 6.2.1 of IEC 11770-4 – the October 2005 draft at least – the equivalent value $c$ is defined as a ...


1

There is an explicit RCF 5054 which uses SRP to negotiate a shared key for a TLS connection. There are also hooks for OpenSSL to be able to use SRP to setup an SSL connection without using certificates using the SRP generated shared session key.


1

Look at where $a$ is used in the protocol: The user calculates the public $A = g^a$ using it. The user computes the session key as $K = H(S)$, with $S = (B - kg^x) ^ {a + ux}$. An attacker should never find out $S$, because even if the session key $K$ leaks due to e.g. a flawed encryption algorithm, she would only know the hashed value. So knowing or ...



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