Tag Info

Hot answers tagged

4

This has been specified by the standard, steps 4 and 5 of the protocol described in RFC 4253: S generates a random number y (0 < y < q) and computes f = g^y mod p. S receives e. It computes K = e^y mod p, H = hash(V_C || V_S || I_C || I_S || K_S || e || f || K) (these elements are encoded according to their types; see below), ...


3

What you have here is indeed a structure called SubjectPublicKeyInfo. It's usually part of an X.509 certificate, but it is often also used separate from a certificate. It's, for instance, the default encoding for RSA public keys in Java and - if I'm not mistaken - OpenSSL. You can view the complete structure here and compare it with the SubjectPublicKeyInfo ...


3

I'm assuming you mean a base 64 encoded key file, since removing the newlines from a binary file would obviously break things. The RSA standards (e.g. RFC 2459) only define a binary representation for keys. In practice, like OpenPGP keys (RFC 4880), they are often encoded in base 64 using the otherwise obsolete PEM standards (RFC 1421). The PEM printable ...


3

The MAC is NOT redundant. As alluded to by PaĆ­lo Ebermann's comment, the word authentication has a different meaning in the two scenarios you mentioned. In the key exchange phase of SSH, the purpose of authentication is to ensure to both parties that they are indeed talking to the right peer (if using mutual authentication). Typically, the server ...


2

Your example is missing something: your two calls to the OpenSSL library are entirely entirely independent, but your calls to the mcrypt library reuse an existing handle. CBC has the property that identical plaintext blocks are exceedingly unlikely to encrypt to the same value due to chaining of the previous output into the next input. Your OpenSSL calls ...


2

I don't think there is a dedicated name for this. If I had to find a word, it would probably be "stateful" or "with explicit state". What you observe is actually the usual case: The user initializes an encryption system with a key, resulting in some state of the system. Then, each time the user wishes to encrypt some data, he has to pass the current state ...


2

Both the AES key size and the RSA key size matter, because it's no use adding security beyond the weakest link. Here the weakest link is 2048-bit RSA, which is considered roughly equivalent in security to 100-128-bit symmetric keys (depending on who you ask). So having a password with much more than 100 bits of entropy would be fairly useless. In practice, ...


1

In ssh-keygen.c of the OpenSSH source code, there is the following call: if (prime_test(in, out, rounds == 0 ? 100 : rounds, generator_wanted, checkpoint, start_lineno, lines_to_process) != 0) ...and a comment for the function prime_test says: * perform a Miller-Rabin primality test Therefore, it does indeed use a ...


1

In addition to yyyyyyy's answer, there is also probabilistic encryption, in which the encryption process incorporates some randomness. That allows many identical messages with the same key to be encrypted differently; it doesn't necessarily encrypt the same text differently in the same message (it might encrypt $a+a$ as $E(a)+E(a)$), but it does let you send ...



Only top voted, non community-wiki answers of a minimum length are eligible