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You tried interpreting this as a ternary code written in columns, but why not in rows? It was really quite simple to solve. Here's the code I used: for n in ['110','012','111','120','112','001','011','012']: x = int(n,3) + 64 if x==64: x=32 print chr(x), and here's the answer:


It will depend entirely on the specific encryption scheme. There is really no theoretical reason why a ciphertext should not be clearly identifiable as being a ciphertext and not a plaintext. In fact, take any encryption scheme and modify it so that the encryption algorithm works as before, only it appends to the ciphertext the string "THIS IS A ...

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