# Tag Info

The original question was: Alice knows: $a,b$ and $x$ such that $a^{(x\cdot x)} = b$ Bob knows: $a,b$ and DrLecter referenced this paper (fixed the link), which covers the question. Now, the question was changed to Alice knows: $b$ and $x$ such that $x^x=b$; Bob knows: $b$. The given structure was: ... multiplicative group $G$ ...