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seen Jan 19 at 22:52

Jan
19
accepted Why is this authentication procedure using Rabin crypto not useful?
Jan
19
comment Why is this authentication procedure using Rabin crypto not useful?
I understand your clarification, lets assume the challenger chooses $m$ and computes everything and sends r to A, is it still not useful?
Jan
19
comment Why is this authentication procedure using Rabin crypto not useful?
I am not 100% sure how this can be interpreted, but in the case that $r$ is a quadrtic residue, is there anything strange in the method?
Jan
19
asked Why is this authentication procedure using Rabin crypto not useful?
Jan
18
awarded  Supporter
Jan
18
accepted One-time pad mistake in the transmission?
Jan
18
accepted RSA cipher wrong use
Jan
18
comment RSA cipher wrong use
Thank you very much, it is clear now to me.
Jan
18
comment RSA cipher wrong use
Thanks for your answer. I mean that before we use RSA I encode the message by converting each letter of the message to an integer (space=0, a=1,b=2,c=3,...) and then encrypting this integer $k$ as $k^e \mod N$ where $N=pq$ for p,q primes and $e$ is the encrypting exponent. Why is this procedure not effective?
Jan
18
comment One-time pad mistake in the transmission?
Thanks for your answer. How would the attacker proceed at the point he has access to both sequences?
Jan
18
asked RSA cipher wrong use
Jan
18
asked One-time pad mistake in the transmission?
Nov
26
awarded  Student
Nov
26
awarded  Scholar
Nov
26
accepted Upper bound Linear Feedback Shift Register
Nov
26
comment Upper bound Linear Feedback Shift Register
One think that is not 100% clear; In the case that the upper bound is achieved, why is it then achieved by any non-zero initial vector?
Nov
26
comment Upper bound Linear Feedback Shift Register
With $R$ registers I mean, that each of them contain one value from the finite field $\mathbb F_q$. Initially these contain the values $x_0,...,x_{R-1}$ which is called the initial fill. At each time step, the values in the registers are shifted down and the final register is filled by a new value determined by the old values in all of the registers. I hope this explains the term.
Nov
26
asked Upper bound Linear Feedback Shift Register