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Dec
23
awarded  Autobiographer
Nov
16
comment How does a Hashing algorithm always result in a digest in a fixed size?
@StephenTouset That makes sense. Could you give an example of how that process would work if the string being hashed is smaller than the digest size? AKA, how does "hello" (5 bytes) turn into a 16 or 20 byte digest in the case of MD5 and SHA1, respectively.
Nov
16
asked How does a Hashing algorithm always result in a digest in a fixed size?
Nov
16
awarded  Popular Question
Nov
16
awarded  Popular Question
Sep
17
accepted What are the practical limitations of Asymmetric encryption vs Symmetric encryption?
Sep
16
asked What are the practical limitations of Asymmetric encryption vs Symmetric encryption?
Aug
17
awarded  Yearling
Aug
17
accepted What is the difference between a PRF and a PRF+?
Jul
27
awarded  Popular Question
Jul
7
comment What is the difference between a PRF and a PRF+?
Also, a follow on question: Is it safe to understand IKEv2's definition of PRF+ and IKEv1/TLS's definition of PRF as to mean the same thing? Are both simply each individual protocol's strategy to create a arbitrary length output which is always identical if starting with identical inputs?
Jul
7
comment What is the difference between a PRF and a PRF+?
Hi Poncho, thanks for the answer. I am was nearly going to mark it as the right answer, but I'm still not sure I fully understand your answer. I don't suppose you could dumb it down just a bit, write it to a target audience that isn't as well versed in crypto or college math?
Jul
7
asked What is the difference between a PRF and a PRF+?
Jun
17
awarded  Popular Question
Jan
4
accepted How does ECDH arrive on a shared secret?
Jan
4
comment How does ECDH arrive on a shared secret?
To avoid continuing the back and forth in Comments, I created a Chat Room and have posted a few more questions there.
Jan
4
comment How does ECDH arrive on a shared secret?
I see... ok, just to again make sure I understand.. and thanks to @StephenTouset's nugget of wisdom (thanks Stephen!). When Alice is dotting $g$ to itself $a$ times, Alice isn't really doing the "dot" operation $a$ times, but is somehow using a magical math formula that gets Alice $A$ much quicker than actually doing the "dot" $a$ times. So the final $S$ from Alice's perspective is $g$ dot $g$ $b$ times to get $B$ (supplied by Bob), then $B$ dot $B$ $a$ times. And from Bob's: $A$ dot $A$ $b$ times. Which ends up at the same point in the curve... the shared secret.
Jan
4
comment How does ECDH arrive on a shared secret?
Let me just confirm I understand you...Everyone knows the starting point ($g$), everyone knows where Alice ended up ($A$), everyone knows where Bob ended up ($B$), and everyone knows the actual elliptic curve. But only Alice knows how many iterations of "dot" she did ($a$), and only Bob knows how many iterations he did ($b$). And once they know each other's $A$ and $B$, they then continue the other's "dot" operation. AKA, Alice takes $g$ and $B$ and "dots" it $a$ more times, and Bob takes $g$ and $A$ and "dots" it $b$ more times, and they both land at $S$, the shared secret... is that it?
Jan
4
revised How does ECDH arrive on a shared secret?
added two <BR> tags for formatting
Jan
4
asked How does ECDH arrive on a shared secret?