neverwalkaloner
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# 49 Actions

 Apr1 awarded Yearling Apr1 revised Decrypt AES-128 with key file but missing IV? edited body Apr1 answered Decrypt AES-128 with key file but missing IV? Mar20 revised In Needham Schroeder key distribution what happens if responder's part is not encrypted in step 2 with Kbs but encrypted instead by Kab in step 3 deleted 5 characters in body Mar20 revised In Needham Schroeder key distribution what happens if responder's part is not encrypted in step 2 with Kbs but encrypted instead by Kab in step 3 added 16 characters in body Mar20 answered In Needham Schroeder key distribution what happens if responder's part is not encrypted in step 2 with Kbs but encrypted instead by Kab in step 3 Mar18 awarded Enthusiast Mar12 answered Linear Cryptanalysis - possible without plaintext? Mar10 comment Why the same characteristics cannot be used to recover all FEAL4 keys @Thomas Thanks for answer, but I did not get, what do you mean. Do you mean that differential 0x8080000080800000, which used for cracking subkey of last round, leads to the differential 0x02000000 with 100% probability? And so we cannot reveal subkey of round 2? But why we cannot use this differential to reveal subkey of round 3? Mar10 awarded Student Mar10 revised Why the same characteristics cannot be used to recover all FEAL4 keys added 210 characters in body Mar10 asked Why the same characteristics cannot be used to recover all FEAL4 keys Mar6 comment why inverse in diffie-hellman protocol will not give same value? For more clarity could you update your question? Do you mean why $g^{a(bb^{-1})} !=g^a\bmod P$ or why $g^{(abb)^{-1}} !=g^a\bmod P$. Mar6 comment why inverse in diffie-hellman protocol will not give same value? @tylo, I understood, what did you talked about. Thank you. Mar6 revised why inverse in diffie-hellman protocol will not give same value? added 207 characters in body Mar6 awarded Commentator Mar6 comment why inverse in diffie-hellman protocol will not give same value? @tylo for example $P=29, g=3, a=2, b=5$. $g^a =9 \bmod 29$, $g^{ab} =5 \bmod 29$. $b^{-1} = 6 \bmod 29$. But $g^{abb^{-1}}=23 \bmod 29$ If DrLecter is right and my answer is wrong, could you explain please, why last result is not equal to 9. Is something i messed or done wrong? Mar6 revised why inverse in diffie-hellman protocol will not give same value? added 17 characters in body Mar6 comment why inverse in diffie-hellman protocol will not give same value? @Aria, I added intermediate steps. Hope, now it is more clear. Mar6 revised why inverse in diffie-hellman protocol will not give same value? added 32 characters in body