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Apr
25
comment Can a proof be constructed to show there is no distinguisher?
Yeah, I was wondering if there were 'real' arguments for 'real' hashing functions that showed one did not contain a distinguisher that another is susceptible to.
Apr
24
comment Can a proof be constructed to show there is no distinguisher?
1 - This isn't a homework question. I asked because I was wondering if such proofs are constructed for hash functions. 2 - If it was a homework, the homework would have been turned in long ago - the question was first asked over a year ago!