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accepted Why do we need in RSA the modulus to be product of 2 primes?
Oct
27
comment Why do we need in RSA the modulus to be product of 2 primes?
Oh.... so because the attacker would know $\phi(N)$, he would be able to deduce $d$ from $e$ because $de=1$ in mod $\phi(N)$. I think I am starting to get it.
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asked Why do we need in RSA the modulus to be product of 2 primes?