Karel Bílekless info
|visits||member for||1 year, 9 months|
|seen||Jul 11 at 0:52|
|bio||website||karelbilek.com||visits||member for||1 year, 9 months|
|location||seen||Jul 11 at 0:52|
Why do we need in RSA the modulus to be product of 2 primes?
Oh.... so because the attacker would know $\phi(N)$, he would be able to deduce $d$ from $e$ because $de=1$ in mod $\phi(N)$. I think I am starting to get it.