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Nov
11
awarded  Editor
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11
revised Can there be two hash functions without common collisions?
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Nov
8
comment Can there be two hash functions without common collisions?
Stephen, that actually depends. If the pigeon hole argument applies, then of course any hash has a collision. If we can restrict the input space to be not bigger than the output space then this is not true: consider the function F(x) = 0 which makes G(x) = x.
Nov
8
awarded  Teacher
Nov
2
answered Can there be two hash functions without common collisions?