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seen Jun 11 at 12:58

Jan
7
accepted Break double encryption
Jan
7
comment Break double encryption
It will take $O(2^{2n-m})$ but with low (non neglectable) probability, while using $n$ entries will have very high probability (almost 1).
Jan
7
revised Break double encryption
added 2 characters in body
Jan
7
revised Break double encryption
added 191 characters in body
Jan
6
comment Break double encryption
@PaĆ­loEbermann , Do you think I should edit my question so it will not look like an homework assignment but more like a cryptographic problem?
Jan
6
revised Break double encryption
added 7 characters in body
Jan
6
revised Break double encryption
added 2 characters in body
Jan
6
asked Break double encryption
Dec
30
awarded  Scholar
Dec
30
awarded  Supporter
Dec
30
accepted What do $0^n$ and $1^n$ mean in cryptography?
Dec
30
comment What do $0^n$ and $1^n$ mean in cryptography?
@AFS Thank you! that is what i wanted to know. Please write it as a separate answer so i will be able to accept it and rate it. Can you explain why different strings are needed? What is the concept that is being achieved with different strings?
Dec
29
revised What do $0^n$ and $1^n$ mean in cryptography?
added 47 characters in body
Dec
29
awarded  Editor
Dec
29
revised What do $0^n$ and $1^n$ mean in cryptography?
added 154 characters in body
Dec
29
comment What do $0^n$ and $1^n$ mean in cryptography?
I will try to rewrite the question so it will be more clear.
Dec
29
awarded  Student
Dec
28
comment What do $0^n$ and $1^n$ mean in cryptography?
Why always in cryptography $1^k$ and $0^k$ are used? do they have a symbolic value? that the part that confuses me.
Dec
28
comment What do $0^n$ and $1^n$ mean in cryptography?
yeah but what is the meaning of those strings inside the above equation? why $0^k$ and not $0^{k-1}$1 ?
Dec
28
asked What do $0^n$ and $1^n$ mean in cryptography?