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Sep
7
comment ElGamal signature - exploiting fallacious implementation
Please, correct me if I am wrong. We find a $\gamma$ satisfying $\gamma \equiv 1 \pmod{p-1}$ and $\gamma \equiv \alpha^x \pmod{p}$ and we are done.
Sep
7
accepted KeeLoq showing that decryption is indeed the inverse of encryption
Sep
7
awarded  Scholar
Sep
7
accepted ElGamal signature without calculating the inverse
Sep
7
asked ElGamal signature - exploiting fallacious implementation
Sep
6
awarded  Supporter
Sep
5
awarded  Student
Sep
5
asked ElGamal signature without calculating the inverse
Sep
3
asked KeeLoq showing that decryption is indeed the inverse of encryption