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Jul 11, 2023 at 5:31 vote accept vimwitch
Apr 10, 2023 at 5:22 comment added Daniel S There’s an even easier first pre-image attack. Consider the hash of $k$ copies of $x$.
Apr 9, 2023 at 17:29 comment added fgrieu That was not my idea about first preimage resistance for 2. Rather, it's that if $H$ has $n$ bits, there is a first preimage attack with expected cost like $2^{n/2}$ hashes somewhat like for the birthday problem.
S Apr 9, 2023 at 15:15 review First answers
Apr 12, 2023 at 15:26
S Apr 9, 2023 at 15:15 history edited vimwitch CC BY-SA 4.0
update first preimage problem
Apr 9, 2023 at 15:09 history edited vimwitch CC BY-SA 4.0
update first preimage problem
S Apr 9, 2023 at 15:02 review First answers
Apr 9, 2023 at 15:14
S Apr 9, 2023 at 15:02 history answered vimwitch CC BY-SA 4.0