Timeline for Reordering non-block-aligned parts with DES in ECB mode
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 23, 2014 at 9:02 | answer | added | Ilmari Karonen | timeline score: 3 | |
| Jul 23, 2014 at 3:31 | answer | added | Antikithira | timeline score: -4 | |
| Feb 14, 2014 at 23:15 | comment | added | Brock Hansen | 7 such lines would be 287 bytes. If there are, as you say, only 6 newlines, not 7, that would be 286 bytes. In either case, if the ciphertext is 288 bytes there must be some padding. What padding was used? How sure are you that it's not 7 40-byte lines without newlines, followed by 1 newline that's been padded out to 8 bytes? | |
| Nov 3, 2013 at 21:21 | comment | added | Maarten Bodewes♦ | I remember - I think from stackoverflow - that this was a misinterpretation of the question. Can you confirm that and possibly delete this question if it has been solved? | |
| Oct 14, 2013 at 3:21 | history | tweeted | twitter.com/#!/StackCrypto/status/389591809678385152 | ||
| Oct 8, 2013 at 3:03 | review | Close votes | |||
| Oct 9, 2013 at 17:56 | |||||
| Oct 3, 2013 at 16:24 | comment | added | deed02392 | I figure you need to identify the ciphertext in a block for a newline character, as when you move the first line to the end of the file, you need to insert it after byte 40. | |
| Oct 3, 2013 at 5:40 | comment | added | user31478 | @D.W. This is an specific exercise. I understand that you can swap ciphertext blocks and the associated plaintext blocks will also be swapped accordingly. However, my issue is that I want to swap the last and first lines. There are 40 bytes in the first line (each line) so that's 5 encrypted blocks followed by a newline character which would be included in the next block? wouldn't that make it so i cant just select the last line on it's own? the first chunk would include some of that last lines plaintext as well? and doesn't the last chunk of the last line have padding bits that can't bemoved? | |
| Oct 3, 2013 at 5:14 | comment | added | D.W. | Can you tell me the context where you ran into this? What makes you think it is possible to exchange the first line with the last? Why are you so set on that specific goal? That seems awfully specific (as opposed to, say, swapping some pair of entries of the attacker's choice). I assume you know that you can swap any pair of ciphertext blocks, and the corresponding plaintext blocks will be swapped? So if you can find a pair of blocks that, when swapped, leaves the format of the plaintext undisturbed (and such that the exchange is favorable to the attacker), that's a valid attack. | |
| Oct 2, 2013 at 23:57 | review | Close votes | |||
| Oct 3, 2013 at 0:34 | |||||
| Oct 2, 2013 at 22:27 | history | edited | Gilles 'SO- stop being evil' | CC BY-SA 3.0 |
deleted 122 characters in body; edited tags; edited title
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| Oct 2, 2013 at 22:24 | history | migrated | from security.stackexchange.com (revisions) | ||
| Oct 2, 2013 at 22:19 | comment | added | Gilles 'SO- stop being evil' | @Xander This isn't a brain teaser, it's a serious crypto question. It would be on-topic on Cryptography. Please don't repost, I've flagged for migration. | |
| Oct 2, 2013 at 21:53 | comment | added | user31478 | @Xander I'll post it there. Would the best practice be to delete this post? | |
| Oct 2, 2013 at 21:37 | comment | added | Xander | This is a security specific topic certainly, but code golf type questions or questions about breaking specific systems or working with a specific ciphertext are indeed off topic here. It might be a better fit at the Programming Puzzles site. | |
| Oct 2, 2013 at 21:12 | history | asked | user31478 | CC BY-SA 3.0 |