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Nov 2, 2023 at 8:02 vote accept qiuxicj
Oct 27, 2023 at 2:15 comment added qiuxicj Thanks for your help! You are right. But how can I figure out the basis of $\Lambda$ and why is the volume $q^m$. Since $ L(A\vert I_m\vert -b)\subset L(I_{kn + m + 1})$, by corollary 2.7 (2) in the different ideal, that is $L_1 \subset L_2 \Longleftrightarrow L_2^\lor \subset L_1^\lor$, so I can sure $L(A\vert I_m\vert -b)^\lor \supset L(I_{kn + m + 1})^\lor = L(I_{kn + m + 1})$.
Oct 26, 2023 at 10:50 history answered Daniel S CC BY-SA 4.0