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Oct 30, 2013 at 6:30 vote accept student
Oct 29, 2013 at 6:41 comment added student Yes, your answer is clearly correct in terms that were used in the question. However, it seems that I have put it wrong in the first place. What about the case when we are interested in $P((X,Y),(Y,Z))$ such that $P((X=x,Y=y), (Y=y, Z=z)) = P((X=x, Y=y)) P((Y=y, Z=z)|X=x, Y=y)$ and $P((X=x,Y=y), (Y=y_2, Z=z)) = 0$ if $y \neq y_2$?
Oct 28, 2013 at 16:17 history answered poncho CC BY-SA 3.0