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S Mar 14 at 10:23 history suggested CommunityBot CC BY-SA 4.0
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S Mar 14 at 10:23
Nov 8, 2013 at 2:01 comment added Samuel Neves A sphere ($x^2 + y^2 + z^2 = 1$) would still not be secure; however, if you intersect two quadric surfaces (i.e. surfaces defined by quadratic polynomials) you actually can get a secure curve, which --- guess what --- is actually an elliptic curve! The Jacobi intersection curves are an example of this.
Nov 6, 2013 at 15:55 comment added stackuser So elliptic curves are like the sweet spot over a continuum of equations that might be used over a group. That continuum seems like it ranges from "way too expensive for computation" (hyper/super elliptic curves) to "the DLP is not difficult enough" (putting P and Q over a conic section or circle). Although your conic section made me wonder why a sphere in $R^{3}$ wouldn't work, too expensive perhaps. +1 and accepted.
Nov 5, 2013 at 23:17 vote accept stackuser
Nov 5, 2013 at 7:21 history answered Samuel Neves CC BY-SA 3.0