Timeline for What exactly does a key do?
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
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| Jun 17, 2020 at 8:17 | history | edited | CommunityBot |
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| Jul 12, 2014 at 15:17 | vote | accept | Wad | ||
| Jul 12, 2014 at 15:16 | vote | accept | Wad | ||
| Jul 12, 2014 at 15:17 | |||||
| Jul 11, 2014 at 11:38 | history | tweeted | twitter.com/#!/StackCrypto/status/487561445601980417 | ||
| Jul 8, 2014 at 20:48 | comment | added | Paŭlo Ebermann | @Wad: yes, one of the 26 keys (the "shifting by 0" one) would be a weak key, which doesn't change anything. If you are encrypting only a single letter, then this is just a valid key as all other ones. | |
| Jul 8, 2014 at 20:29 | answer | added | fkraiem | timeline score: 2 | |
| S Jul 8, 2014 at 19:55 | history | edited | Gilles 'SO- stop being evil' | CC BY-SA 3.0 |
added tags and latex formatting
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| S Jul 8, 2014 at 19:55 | history | suggested | 9fpqhijf7zm1qrgn760r2hzipi92n7 | CC BY-SA 3.0 |
added tags and latex formatting
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| Jul 8, 2014 at 18:05 | review | Suggested edits | |||
| S Jul 8, 2014 at 19:55 | |||||
| Jul 8, 2014 at 16:36 | comment | added | Wad | OK, just thinking about why you say there are 26 keys: I assume it is the number added to the input character to get the output character: in this case, wouldn't there actually be 25 keys: since if there were 26, adding 26 to a letter would result in the same letter, assuming we 'cycle' around? Or have I misunderstood where you get 26 from? | |
| Jul 8, 2014 at 16:19 | answer | added | marstato | timeline score: 3 | |
| Jul 8, 2014 at 15:36 | comment | added | CodesInChaos | If you have an $b$ bit key, there are $2^b$ possibilities. The base 2 logarithm $\log_2$ is the inverse of the exponential function $2^x$. So with 26 possible keys, you get $\log_2{26} \approx 4.7$ or equivalently $2^{4.7} \approx 26$. | |
| Jul 8, 2014 at 15:22 | review | First posts | |||
| Jul 8, 2014 at 16:03 | |||||
| Jul 8, 2014 at 15:12 | comment | added | Wad | OK, that makes a bit more sense. thanks. Could you please tell me where the log calculation comes from? | |
| Jul 8, 2014 at 15:09 | comment | added | CodesInChaos | In that sample you could consider "Shift by $x$" the algorithm (Caesar encryption) and $x=2$ the key. This would be a $\log_2{26}\approx4.7$ bit key. | |
| Jul 8, 2014 at 15:05 | history | asked | Wad | CC BY-SA 3.0 |