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Oct 1, 2021 at 4:21 history edited Patriot CC BY-SA 4.0
removed internet slang because it might confuse some readers; concision
Jun 27, 2017 at 12:52 vote accept wlad
Jul 8, 2015 at 10:24 history tweeted twitter.com/#!/StackCrypto/status/618727404756946944
Jul 7, 2015 at 17:39 comment added SEJPM We want as much security as we can have (with "negligible" effort). Just to be sure. Textbook RSA by itself isn't even IND-CPA, because you can find low-entropy messages by trying them out (=academically broken). If you also consider this: Assuming you use e=3 and send the exact same message to three other people (hybrid encryption, one symmetric key), then everyone having all three (encrypted) messages can read the message.
Jul 7, 2015 at 17:33 answer added Yehuda Lindell timeline score: 22
Jul 7, 2015 at 17:19 history edited wlad CC BY-SA 3.0
[Edit removed during grace period]
Jul 7, 2015 at 17:07 comment added wlad @SEJPM so for random session keys, textbook RSA is CPA-secure but not CCA-secure and it's the latter we want.
Jul 7, 2015 at 17:06 comment added SEJPM ... and please don't forget. The scheme broken by Bleichenbacher was way stronger than textbook RSA.
Jul 7, 2015 at 16:58 comment added SEJPM This would still be vulnerable to CCA attacks and was at least exploited once. So we make sure we miss nothing and it's always secure and make it IND-CCA2 (by using OAEP)
Jul 7, 2015 at 16:49 history asked wlad CC BY-SA 3.0