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e-sushi
e-sushi
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I think that I've realised why you might calculate pi. It's easy$\pi$.

x^2 + y^2 = 1It's easy: $x^2 + y^2 = 1$ is a simple calculation, thus fast. IfIf you pickedwould pick another 2 dimensional shape with a non trivial perimeter, you'dyou'ld have a harder time estimating which side of the perimeter a point had fallen.

I think that I've realised why you might calculate pi. It's easy.

x^2 + y^2 = 1 is a simple calculation, thus fast. If you picked another 2 dimensional shape with a non trivial perimeter, you'd have a harder time estimating which side of the perimeter a point had fallen.

I think that I've realised why you might calculate $\pi$.

It's easy: $x^2 + y^2 = 1$ is a simple calculation, thus fast. If you would pick another 2 dimensional shape with a non trivial perimeter, you'ld have a harder time estimating which side of the perimeter a point had fallen.

Making a stand...
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Paul Uszak
Paul Uszak
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I think that I've realised why you might calculate pi. It's easy.

x^2 + y^2 = 1 is a simple calculation, thus fast. If you picked another 2 dimensional shape with a non trivial perimeter, you'd have a harder time estimating which side of the perimeter a point had fallen. (Ya think?)

I think that I've realised why you might calculate pi. It's easy.

x^2 + y^2 = 1 is a simple calculation, thus fast. If you picked another 2 dimensional shape with a non trivial perimeter, you'd have a harder time estimating which side of the perimeter a point had fallen. (Ya think?)

I think that I've realised why you might calculate pi. It's easy.

x^2 + y^2 = 1 is a simple calculation, thus fast. If you picked another 2 dimensional shape with a non trivial perimeter, you'd have a harder time estimating which side of the perimeter a point had fallen.

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Paul Uszak
Paul Uszak
  • 15.7k
  • 2
  • 30
  • 82

I think that I've realised why you might calculate pi. It's easy.

x^2 + y^2 = 1 is a simple calculation, thus fast. If you picked another 2 dimensional shape with a non trivial perimeter, you'd have a harder time estimating which side of the perimeter a point had fallen. (Ya think?)