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Jul 27, 2016 at 21:49 history tweeted twitter.com/StackCrypto/status/758419024296472576
Jul 27, 2016 at 15:18 history edited e-sushi CC BY-SA 3.0
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Oct 21, 2015 at 18:46 comment added Dig @SEJPM A small mistake: PRF security doesn't guarantee that you won't be able to find the input faster than brute-force. It simply state that there exists no polynomial-time algorithm that will be able to distinguish between the PRF and a random function. Note that there might be a subexponential algorithm (which will be much faster than brute-force) that might be able to distinguish and even retrieve the key, and the PRF will be considered secure nevertheless.
Oct 21, 2015 at 9:34 answer added kung_fu_coder timeline score: 2
Oct 21, 2015 at 0:01 answer added user991 timeline score: 4
Oct 20, 2015 at 21:55 comment added SEJPM In this case you shouldn't be able to distinguish prf from a random function and you can't find the input faster than brute-force.
Oct 20, 2015 at 21:53 comment added cryptodog No, you don't have the key $k$.
Oct 20, 2015 at 21:21 comment added SEJPM are you given the key $k$ in the first one? The second one should hold.
Oct 20, 2015 at 21:08 history asked cryptodog CC BY-SA 3.0