When a hardware system is protected by a 4 digits password, what is the advantage of the attacker into breaking that system?

Isn't it $2^{10}*2^{10}*2^{10}*2^{10}=2^{40}$? If $\frac{1}{2^{40}}$ is the $\textit{Adv}$ of the attacker then is this reasonable computation for the attacker? In my eyes this seems like a simple brute force attack for 4 numbers. I mean is super easy. Isn't it?

When a hardware system is protected by a 4 digits password, what is the advantage of the attacker into breaking that system?

Isn't it $10*10*10*10=10^{4}$? If $\frac{1}{10^{4}}$ is the cost of such an attack then is this reasonable computation for the attacker? In my eyes this seems like a simple brute force attack for 4 numbers. I mean is super easy. Isn't it?

When a hardware system is protected by by a 4digit password what is the advantage of the attacker into breaking that system?Isn't it $2^{10}*2^{10}*2^{10}*2^{10}=2^{40}$. If $\frac{1}{2^{40}}$ is the $\textit{Adv}$ of the attacker then is this reasonable computation for the attacker? In my eyes this seems like a simple brute force attack for 4 numbers. I mean is super easy.Isn't it?

When a hardware system is protected by a 4 digits password, what is the advantage of the attacker into breaking that system?

Isn't it $2^{10}*2^{10}*2^{10}*2^{10}=2^{40}$? If $\frac{1}{2^{40}}$ is the $\textit{Adv}$ of the attacker then is this reasonable computation for the attacker? In my eyes this seems like a simple brute force attack for 4 numbers. I mean is super easy. Isn't it?

When a hardware system is protected by by a 4digit password what is the advantage of the attacker into breaking that system?Isn't it $2^{10}*2^{10}*2^{10}*2^{10}=2^{40}$. If this is the $\textit{Adv}$ of the attacker then is this reasonable cost? In my eyes this seems like a simple brute force attack for 4 numbers. I mean is super easy.Isn't it?

When a hardware system is protected by by a 4digit password what is the advantage of the attacker into breaking that system?Isn't it $2^{10}*2^{10}*2^{10}*2^{10}=2^{40}$. If $\frac{1}{2^{40}}$ is the $\textit{Adv}$ of the attacker then is this reasonable computation for the attacker? In my eyes this seems like a simple brute force attack for 4 numbers. I mean is super easy.Isn't it?