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Apr 4, 2017 at 22:13 history tweeted twitter.com/StackCrypto/status/849384429726429187
Apr 2, 2017 at 18:58 history edited Ilmari Karonen CC BY-SA 3.0
we have mathjax here, we don't need all that extra HTML; also add citation to quote
Mar 16, 2016 at 12:09 comment added Mok-Kong Shen I wonder how you got the value 88. If the block size of the plaintext material is mb bits (mb even), It is practically easy to obtain an RSA modulus n (n > 2**mb) that has mb + 2 bits. See Example 2 in Appendix of s13.zetaboards.com/Crypto/topic/7234475/1/ This implies that the differences between the bit sizes of successive elements in the sequence of RSA moduli could be as small as 2.
Mar 15, 2016 at 21:30 history edited Maarten Bodewes CC BY-SA 3.0
formatting, title
Mar 15, 2016 at 14:53 comment added Achille ishak @Mok-KongShen thanks, I agree with you. i taught i can find other ideas for the same key size. since increasing size is not very suitable and i tested it. must every time increase at least by 88 bit.
Mar 15, 2016 at 14:46 vote accept Achille ishak
Mar 15, 2016 at 13:25 comment added Mok-Kong Shen If you have a sequence of RSA moduli that are strictly increasing and you have plaintext materials seperated into blocks of a constant size that is smaller than the least modulus, you could evidently do that multiple RSA encryption in the ordering of the sequence of the moduli..
Mar 15, 2016 at 9:31 answer added user991 timeline score: 4
Mar 15, 2016 at 8:52 history asked Achille ishak CC BY-SA 3.0