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fixed maths error
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r3mainer
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The second row of the second table gives you the values of $g^e\pmod{11}$ for $0 \le e \le 10$. Notice that $2^{10}\pmod{11} \equiv 2^{0}\pmod{11}$. This means that any multiple of $2^{10}$ raised to any power is congruent to $1\pmod{11}$.

With that in mind, it shouldn't be hard to see that $2^{2652557887263}\pmod{11} \equiv 2^3\pmod{11}$. So the answer is $8$.


P.S. I suspect your question may be slightly off-topic for this site, hence the down votes.

The second row of the second table gives you the values of $g^e\pmod{11}$ for $0 \le e \le 10$. Notice that $2^{10}\pmod{11} \equiv 2^{0}\pmod{11}$. This means that any multiple of $2^{10}$ is congruent to $1\pmod{11}$.

With that in mind, it shouldn't be hard to see that $2^{2652557887263}\pmod{11} \equiv 2^3\pmod{11}$. So the answer is $8$.


P.S. I suspect your question may be slightly off-topic for this site, hence the down votes.

The second row of the second table gives you the values of $g^e\pmod{11}$ for $0 \le e \le 10$. Notice that $2^{10}\pmod{11} \equiv 2^{0}\pmod{11}$. This means that $2^{10}$ raised to any power is congruent to $1\pmod{11}$.

With that in mind, it shouldn't be hard to see that $2^{2652557887263}\pmod{11} \equiv 2^3\pmod{11}$. So the answer is $8$.


P.S. I suspect your question may be slightly off-topic for this site, hence the down votes.

Source Link
r3mainer
  • 2.1k
  • 15
  • 16

The second row of the second table gives you the values of $g^e\pmod{11}$ for $0 \le e \le 10$. Notice that $2^{10}\pmod{11} \equiv 2^{0}\pmod{11}$. This means that any multiple of $2^{10}$ is congruent to $1\pmod{11}$.

With that in mind, it shouldn't be hard to see that $2^{2652557887263}\pmod{11} \equiv 2^3\pmod{11}$. So the answer is $8$.


P.S. I suspect your question may be slightly off-topic for this site, hence the down votes.