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Jan 30, 2017 at 23:56 comment added poncho @curious: this attack does not work against the RFC; the attacker could compute the value $H(0||h_0||h_1)$, however what he has the authentication path for is $H(1 ||h_0||h_1)$; and so he can't generate an authentication path for the value he has. Yes, the new forged tree won't be the same length; however I believe that the RFC has variable height Merkle trees, hence the attacker submitting a shorting tree isn't an issue.
Jan 30, 2017 at 23:11 comment added curious If that is the case then the new forged tree won't be of the same length of the original one, so the will be captured in the verification phase
Jan 30, 2017 at 23:00 comment added curious Do you mean the adversary can plug into a new tree the value $H(h_0||h_1)$ as a leaf node, and claim a valid hash tree? If that is the case what prevents him from computing the value $H(0||h_0||h_1)$ and plug it into the new tree, which is a valid hash?
Jan 30, 2017 at 22:57 comment added curious It is not clear to me. Why $h_0||h_1$ can be forged and not $0||h_0||h_1$?
Jan 30, 2017 at 22:35 history answered poncho CC BY-SA 3.0