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Jun 20, 2017 at 14:08 vote accept lioness99a
Apr 13, 2017 at 12:48 history edited CommunityBot
replaced http://crypto.stackexchange.com/ with https://crypto.stackexchange.com/
Mar 24, 2017 at 8:44 comment added lioness99a @K.G. That's the conclusion I'm rapidly coming to! But yes, it is definitely helping my understanding while I don't have any knowledge of lattices
Mar 23, 2017 at 19:43 comment added K.G. @lioness99a One of my students looked at an implementation, and the scheme is ridiculously inefficient. But you can explain it to almost anyone in 5 minutes, which is great. I use it to introduce people to a lot of concepts related to FHE.
Mar 23, 2017 at 19:39 comment added K.G. @fgrieu Offset is good.
Mar 23, 2017 at 9:03 comment added lioness99a Thanks for the edit, somehow I'd missed that definition in the notation section... Makes a whole lot more sense now! (and for reference, I'm currently playing around with writing a proof-of-concept in Python)
Mar 23, 2017 at 8:55 history edited fgrieu CC BY-SA 3.0
Addition per comment
Mar 23, 2017 at 8:49 comment added fgrieu @K.G.: +1 for nearest multiple of $p$. But distance is non-negative, when the result of that $\bmod$ can be negative.
Mar 23, 2017 at 8:30 comment added K.G. The "mod p" part in this case should not be thought of as a standard modulo (remainder when divided by p), but rather as the distance to the nearest multiple of p.
Mar 22, 2017 at 18:23 history edited fgrieu CC BY-SA 3.0
Polish
Mar 22, 2017 at 18:17 history edited fgrieu CC BY-SA 3.0
The reference gives a defintion of its notation
Mar 22, 2017 at 15:46 history edited fgrieu CC BY-SA 3.0
Simplify
Mar 22, 2017 at 15:40 history edited fgrieu CC BY-SA 3.0
Simplify
Mar 22, 2017 at 14:29 comment added lioness99a Thank you, I'll give it a try. It just seems counterproductive that a concept which will inevitably need to be programmed uses a definition of $\mod{}$ which is non-standard in all major languages
Mar 22, 2017 at 14:26 history answered fgrieu CC BY-SA 3.0