Timeline for Cipher feedback mode with shift registrers
Current License: CC BY-SA 3.0
8 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
May 28, 2017 at 17:56 | comment | added | Ron Bowes | Yup, that sounds right! | |
May 28, 2017 at 17:02 | comment | added | user48297 | Ah ok so if I have 4 blocks of data(512 bits), it would first encrypt the IV and the key and XOR that output with the plaintext, then it would use the output of that XOR operation as the IV for the next 128 bit block of data? Essentially the last output would be the last block of 128 bits? Am I correct? | |
May 27, 2017 at 14:24 | history | migrated | from security.stackexchange.com (revisions) | ||
May 26, 2017 at 15:57 | comment | added | Ron Bowes | It depends on the plaintext length. The plaintext is broken up into blocks (128 bits on AES, 64 bits on DES, etc), and each block of plaintext goes through the process. | |
May 26, 2017 at 9:46 | comment | added | user48297 | Okay so how many cycles is there in CFB mode? In the first figure there is 3 cycles before it outputs the final ciphertext. And also, the Block CIpher Encryption box in that figure, does that represent for example AES and all its operations such as subtypes and mixcolumns? | |
May 26, 2017 at 5:33 | comment | added | dave_thompson_085 | Second is probably the 'bit-shift' or 'partial-block' form of CFB, usually designated with the number of bits like CFB-1 or CFB-8, summarized in wikipedia and detailed in SP800-38a (as cited) and previously in FIPS81 and (TTBOMK originally) FIPS74. | |
May 26, 2017 at 0:56 | vote | accept | CommunityBot | ||
May 25, 2017 at 23:57 | history | answered | Ron Bowes | CC BY-SA 3.0 |