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Jun 9, 2019 at 1:58 comment added Squeamish Ossifrage @Dan Thanks, you are absolutely correct: it was a typo! Fixed.
Jun 9, 2019 at 1:57 history edited Squeamish Ossifrage CC BY-SA 4.0
Fix typo.
Jun 8, 2019 at 22:17 comment added Dan @SqueamishOssifrage: you've posted an abundance of incredibly useful and helpful on this forum (some of which I actually understood ;-) ). anyway -- under "Encryption", you wrote compute a temporary session key π‘˜=𝐻([𝑑]𝐡)=𝐻([𝑑⋅𝑏]𝐡), and transmit 𝑇 -- seems that there might be typo? Seems like π‘˜=𝐻([𝑑]𝐡)=𝐻([𝑑⋅𝑏]P) might be the intent? Always intimidating to post a suggested correction to an expert, sorry if I missed the boat here.
Nov 7, 2017 at 19:05 history edited Squeamish Ossifrage CC BY-SA 3.0
Tweak placement of wording about $E(k)$. Replace accidental $a[X]$ by $[a]X$.
Nov 6, 2017 at 17:12 comment added Squeamish Ossifrage Yes: secret scalars are always elements of $\mathbb Z/\ell\mathbb Z$. Note that $\ell$ is not a property of the field, although it is limited by the size of the field, according to Hasse's theoremβ€”it is a property of the field and the curve, and may vary from point to point in cases of curves like Curve25519 with composite order. See an earlier answer I wrote for more details on how they are related.
Nov 6, 2017 at 17:03 vote accept Corey Ogburn
Nov 6, 2017 at 16:58 comment added Corey Ogburn So if I understand correctly, if the field is limited by $\ell$ then any private key (Alice's $a$, Bob's $b$ or a temporary key of $t$) larger than $\ell$ is equivalent to that key mod $\ell$, right? Basically any scalar you multiply the generator point by has no benefit to being larger than $\ell$? I'm still processing Example 2, maybe a larger scalar matters there.
Nov 6, 2017 at 16:03 history edited Squeamish Ossifrage CC BY-SA 3.0
Remove an superfluous n.
Nov 5, 2017 at 23:19 history edited Squeamish Ossifrage CC BY-SA 3.0
Answer about encryption too.
Nov 5, 2017 at 23:07 history answered Squeamish Ossifrage CC BY-SA 3.0